#x = -2/3 or x =-2#
It is a quadratic equation (#x^2#), so make it equal to #0#
#3x^2 -4x -4=0#
Find factors if possible first.
#(3x+2)(x-2)=0#
Set each factor equal to #0# and solve for #x#
If #3x+2 =0, rarr x = -2/3#
If #x-2=0, rarr x = 2#
How do you solve #(3x ^ { 2} - 4x ) = 4#?
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